The reverse boost undoes every boost
NOT A NOVELTY CLAIM. This is a machine-checked formalisation, decided by the Lean 4 kernel and depending on no axiom. It is dated and citable. Prior art, where it exists, is cited below. No discovery is claimed.
…and for EVERY event and EVERY boost, proved rather than decided: the theorem above checks eight events under five boosts; this holds for all integers p, q, t, x at once. Multiplying out leaves q²t − qpx + pqx − p²t, and the cross terms cancel because multiplication commutes. A proof, not an exhaustion — it rests on the standard axioms propext and Quot.sound that core's integer lemmas carry.
Proposition
∀ p q t x : Int, boostT (-p) q (boostT p q t x) (boostX p q t x) = (q * q - p * p) * t ∧ boostX (-p) q (boostT p q t x) (boostX p q t x) = (q * q - p * p) * xProof
By by in spacetime.lean. The kernel reduces the proposition and reports no axiom dependency.
Sources and identifiers
- Lean source · src/pair/formal/proofs/spacetime.lean
- Typeset paper · src/research/lean-theorems.tex
- Repository deposit · doi:10.5281/zenodo.21787144
- Author · ORCID 0009-0000-7312-9778
- Deposit record ·
spacetime--the_reverse_boost_undoes_every_boost