Nicomachus sum of cubes is a square
Theorem.Nicomachus sum of cubes is a square — 1³ + 2³ + … + n³ = (n(n+1)/2)².
Proof.1³ + 2³ + … + n³ = (n(n+1)/2)² for every n ≤ 100, both sides computed independently — the sum of the first n cubes is exactly the square of the n-th triangular number.
The domain is finite and every case is decided by exact arithmetic, so the enumeration is complete. ∎
src/9/1/index.ts#discoveredTheoremsWaveTwentyFive
1 · Classification
finite-complete — self-contained computation, no external lean
2 · Provenance
Documented theorem re-derived by exhaustive computation (humanityNovel=false); first-in-this-registry is the only sense of discovered.
Acknowledgment
"Nicomachus sum of cubes is a square" is a re-derivation, acknowledged to documented mathematics — the original proof is the prior art this re-derivation acknowledges; not new to humanity — the contribution is the reproducible computation discoveredTheoremsWaveTwentyFive.
- Prior art
- documented mathematics — the original proof is the prior art this re-derivation acknowledges
- Novelty
- not new to humanity — a re-derivation (humanityNovel = false)
- Contribution
- a reproducible computation (discoveredTheoremsWaveTwentyFive @ src/9/1) that re-derives the result at zero tokens — the contribution is the verifiable recomputation, NOT the theorem
3 · Reproducibility
Recompute from source: npm run theorems:verify recomputes discoveredTheoremsWaveTwentyFive (src/9/1/index.ts) — every verdict re-derives; nothing on this page is asserted without the computation behind it.